Find a parabola's lowest or highest point straight from its equation, and rewrite any quadratic into vertex form when an SAT question asks for a least or greatest value.
Part of the full libraryOpens January 2, 2027 · $97 for a yearWhat’s included
A point on the parabola y equals (x minus 3) squared plus 2 slides down the curve from x equals 6 to x equals 3, while (x minus 3) squared works out to 9, then 4, then 1, then 0, and the point stops at the lowest point, (3, 2). Next, the same parabola's equation, y equals x squared minus 6x plus 11, is rewritten as (x squared minus 6x plus 9) plus 2, which equals (x minus 3) squared plus 2. Then, for y equals negative (x plus 2) squared plus 4, a parabola that opens downward, a gray pointer types 4 as the greatest value of y, and the highest point, (negative 2, 4), is marked. Finally, answer the least possible value of y if y equals x squared plus 10x plus 30, using the buttons after the picture.
y = (x − 3)2 + 2
At x = 6:(6 − 3)2 + 2 = 9 + 2 = 11
You’ll leave with these skills
01Read the vertex and the least or greatest value from vertex form
02Read the vertex when a plus sign is inside the square
03Pick the equivalent form that shows the minimum or maximum
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